[" 8.If "O" is a point within a quadrilateral "ABCD" ,show that "],[OA+OB+OC+OD>AC+BD]

If O is a point within a quadrilateral ABCD, show that OA+OB+OC+OD gt AC+BD.

O is any point inside a rectangle ABCD, Prove that OA^(2) + OC^(2)= OB^(2) + OD^(2)

O is any point inside a rectangle ABCD. Prove that OB^2+OD^2=OA^2+OC^2 .

If 'O' is any point in the interior of rectangle ABCD, then prove that : OB^(2) + OD^(2) = OA^(2) + OC^(2)

O' is any point inside a rectangle ABCD. Prove that OB^2+OD^2=OA^2+OC^2

O is any point inside a rectangle ABCD. Prove that OB^(2)+OD^(2)=OA^(2)+OC^(2) . DEDUCTION In the given figure, O is a point inside a rectangle ABCD such that OB=6cm, OD=8 cm and OA=5 cm, find the length of OC.

In the quad. ABCD is a point inside it. Find that OA+OB+OC+OD>AC+BD.

If 'O' is any point in the interior of rectangle ABCD,then prove that: OB^2+OD^2=OA^2+OC^2 .

O is any point inside a rectangle ABCD.Prove that OB^(2)+OD^(2)=OA^(2)+OC^(2)

In the figure, diagonals AC and BD of quadrilateral ABCD intersect at O such that OB = OD. If AB = CD, then show that ar( Delta DOC) = ar( Delta AOB)