[(cot theta+cos ec theta-1)/(cot theta-c...

[(cot theta+cos ec theta-1)/(cot theta-cos ec theta+1)=sum(1)/(tan^(oo)0^(@))],[" 1) "(sin theta)/(1+cos theta)" 2) "(sin theta)/(1-cos theta)" 3) "(1-cos theta)/(sin theta)" 4) "(cos theta)/(1-sin)]

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(cos theta)/(1-sin theta)=(1+cos theta+sin theta)/(1+cos theta-sin theta)

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(cos theta)/(cos ec theta+1)+(cos theta)/(cos ec theta-1)=2tan theta

(1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)

(sin theta-cos theta+1)/(sin theta+cos theta-1)=(1+sin theta)/(cos theta)

(1+cos theta+sin theta)/(1+cos theta-sin theta)=(1+sin theta)/(cos theta)

(sin theta)/(1-cos theta)=cos ec theta+cot theta

(sin^(2) theta)/(1-cos theta)-(cos^(2) theta)/(1-sin theta)=cos theta-sin theta

1-(sin^(2) theta)/(1+cos theta) + (1+cos theta)/(sin theta) - (sin theta)/(1-cos theta) - (1)/(sec theta)=

prove that (cos theta)/(1-tan theta)+(sin theta)/(1-cot theta)=cos theta+sin theta