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In Dumas’ method for estimation of nitro...

In Dumas’ method for estimation of nitrogen, 0.3g of an organic compound gave 50mL of nitrogen collected at 300K temperature and 715mm pressure. Calculate the percentage composition of nitrogen in the compound. (Aqueous tension at 300K=15 mm)

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Vapour pressure of gas `= 715 - 15`
`= 700 mm`
To calculate the volume of `N_2` at S. T. P.
`V_1 = 50" " mL V_2 = ?`
`p_1 = 700 mm" "p_2 = 760 mm`
`T_1 = 300 K " " T_2 = 273 K`
Applying `(p_1 V_1)/(T_1 ) = (p_2 V_2)/(T_2)`
or `V_2 = (p_1 V_1 T_2)/(p_2 T_1)`
`therefore V_2 = (700 xx 50 xx 273)/(760 xx 300)`
`= 41.9 ` mL
22400 mL of nitrogen at S.T.P. weigh `= 28` g
`41.9` mL of nitrogen at `S. T. P` weigh `= (28 xx 41.9)/(22400)`
`= 0.05 24` g
Percentage of nitrogen `= (0.0524)/(0.3) xx 100= 17.46%`
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