Give hybridisation state of each carbon in following compounds :
(i) `CH_2 = C = O`
(ii) `CH_3 - CH = CH_2`
(iii) `(CH_3)_2 CO`
(iv) `CH_2 = CH CN`
(v) `CH_3 CH_2CH=CH_2`
(vi) `CH_2 = CH_2`
(vii) `CH_3 CH_3`

Explanation

To determine the hybridization state of each carbon in the given compounds, we follow these steps:

### Step-by-Step Solution:

1. **For `CH2 = C = O`:**
- The leftmost carbon (`C1`) is bonded to two hydrogens and has a double bond with the central carbon (`C2`).
- Bonds: 2 sigma (C-H) and 1 pi (C=C) → Total: 3 sigma and 1 pi.
- Hybridization: **sp²**.
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