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In sulphur estimation, 0.157 g of an org...

In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound?

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The correct Answer is:
0.421
Molecular mass of `BaSO_4 = 137 + 32 +64`
`= 233`
233 g of `Ba SO_4` contains ` S = 32` g
. 0.4813 g of `BaSO_4` contains S `= (32)/( 233) xx 0.4813`
`= 0.0661` g
% of Sulphur `= ( 0.0661)/( 0.157) xx 100`
`= 42.10%`
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