An organic compound containing C, H, N and O gave the following results on analysis :
(i) 0.25 g of the compound gave 0.368 g of `CO_2` and 0.205 g of `H_2 O`
(ii) The same weight of the compound gave 31.2 mL of `N_2` at `S. T. P.`
Calculate the percentage composition of the compound.

Answer

C = 40.14%; H = 9.11 %; N = 15.6%; O = 35.15%

Explanation

(i) Percentage of C
`= (12)/( 44) xx ( " Wt. of" CO_2 ) /( "Wt. of compound") xx 100`
`= (12)/( 44)xx ( 0.368)/( 0.25) xx 100`
`= 40.14 %`
(ii) Percentage of `H = (2)/( 18) xx ("Wt. of water")/( " Wt. of compound" xx 100`
`= (2)/( 18) xx (0.205)/( 0.25) xx 100 = 9.11 %`