The IUPAC name for
`CH_3 - overset(O)overset(||)C - CH_2 - CH_2 -overset(O)overset(||)C - OH`

Options

A. 1-hydroxypentane-1, 4-dione
B. 1, 4-dioxopentanol
C. 1-carboxybutan-3-one
D. 4-oxopentanoic acid

Answer

To determine the IUPAC name for the compound `CH3 - C(=O) - CH2 - CH2 - C(=O) - OH`, we will follow these steps:

### Step 1: Identify the longest carbon chain
The longest continuous carbon chain in the compound consists of 5 carbon atoms. This chain includes the carboxylic acid group (-COOH) and the carbonyl group (=O).

### Step 2: Number the carbon chain
We will number the carbon chain starting from the end nearest to the carboxylic acid group to give it the lowest possible number. The numbering will be as follows:
1. Carboxylic acid carbon (C1)
2. Carbonyl carbon (C2)
3. Carbon (C3)
4. Carbon (C4)
5. Methyl group carbon (C5)

So the numbering is:
- C1: -COOH (carboxylic acid)
- C2: C=O (carbonyl)
- C3: CH2
- C4: CH2
- C5: CH3

### Step 3: Identify functional groups
In this compound, we have:
- A carboxylic acid group (-COOH) at C1.
- A carbonyl group (=O) at C2.

### Step 4: Determine the suffix and prefix
The carboxylic acid will take precedence in naming, so we will use the suffix "-oic acid." The carbonyl group will be indicated with the prefix "oxo-."

### Step 5: Combine the names
The longest chain has 5 carbons, which corresponds to "pentane." Since we have a carboxylic acid, the base name will be "pentanoic acid." The carbonyl group at C2 will be indicated as "4-oxo" (since we number from the carboxylic acid end).

### Final IUPAC Name
Putting it all together, the IUPAC name of the compound is:
**4-oxo-pentanoic acid**