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In CH2 = C = CH2, all the carbon atoms a...

In `CH_2 = C = CH_2`, all the carbon atoms are `sp^2` hybridised.

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To determine the hybridization of the carbon atoms in the compound \( CH_2 = C = CH_2 \), we will analyze the bonding and the number of sigma and pi bonds formed by each carbon atom. ### Step-by-Step Solution: 1. **Identify the Structure**: The compound can be represented as: \[ H_2C = C = CH_2 \] ...
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Statement-1: All the hydrogen atoms in CH_(2)=C=CH_(2) lie in one plane. Statement-2: All the carbon atoms in it are not sp^(2) hybridized .

Consider the given statement about the molecule 1. Three carbon atoms are sp^(3) - hybridised 2. Three carbon atoms are sp^(2)- hybridised 3. Two carbon atoms are sp - hybridised

Assertion (A) : All the carbon atoms in H_(2)C=C=CH_(2) are sp^(2) hybridised Reason (R) : In this molecule, all the carbon atoms are attached to each other by double bonds.

What is meant by hybridisation ? Compound CH_(2)=C=CH_(2) contains sp or sp^(2) hybridised carbon atoms. Will it be a planar molecule ?