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An organic compound containing C,H and N...

An organic compound containing C,H and N gave the following analysis
C=40 %,H=13.33 %,N=46.67 %
What would be its empirical formula ?

A

`C_2 H_7 N`

B

`C_2 H_7 N_2`

C

`CH_4 N`

D

`CH_5 N`

Text Solution

Verified by Experts

The correct Answer is:
C
`C : H: N= (40)/( 12) : (13. 33)/( 1) : (46.67)/( 14)`
`= 3.33 : 13.33 : 3.33`
`=1 : 4:1`
Empirical formula `CH_(4) N`
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