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A samlpe of 0.5 of an organic compound w...

A samlpe of 0.5 of an organic compound was analysed using Kjeldahl' method. The ammonia evolved was absorbed in 50 ml of 0.5 M `H_(2)SO_(4)`. The unsused acid after neutralisation by ammonia consumed 80 ml of 0.5N NaOH. Then calculate percentage of nitrogen in organic compound

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The correct Answer is:
B

Unused acid required = 80 mL of 0.5 M NaOH
80 mL of 0.5 M NaOH = 40 mL of 0.5 M `H_2 SO_4`
Volume of acid used = (50 - 40) mL of 0.5 M `H_2 SO_4`
= 10 mL of 0.5 M `H_2 SO_4`
`%` of Nitrogen `= (1.4 xx "Molarity of acid" xx "Basicity" xx "Vol. of acid used")/("Mass of compound taken")`
`= (1.4 xx 0.5 xx 2 xx 10)/( 0.5 ) = 28`
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A sample of 0.50 g of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 mL of 0.5 M H_(2)SO_(4) . The residual acid required 60 mL of 0.5 M solution of NaOH for neutralization. Find the percentage composition of nitrogen in the compound. Strategy: Step 1 . Convert molarity into normality using the relation Normality (N) = n xx Molarity (M) where n factor is either the acidity of base or basicity of acid. Step 2 . Calculate the milliequivalents of NaOH which is equal to the milliequivalents of unreacted H_(2)SO_(4) . Step 3 . Calculate the milliequivalents of total H_(2)SO_(4) and subtract the milliequivalents of unreacted H_(2)SO_(4) to get the milliequivalents of NH_(3) evolved. Step 4 . Calculate the equivalents of NH_(3) , moles of NH_(3) , and moles of N . Step 5 . Calculate the mass of N in the organic compound. Step 6 . Finally, calculate % of N or directly apply Eq. (13.8) or (13.9) to get the % of N in the organic compound.

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