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1.2 g of an organic compound on Kjeldahl...

1.2 g of an organic compound on Kjeldahlization liberates ammonia which consumes 30 `cm^3` of 1 N HCI. The percentage of nitrogen in the organic compound is

A

30

B

35

C

46.67

D

20.8

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The correct Answer is:
To find the percentage of nitrogen in the organic compound using the Kjeldahl method, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Data:** - Mass of the organic compound = 1.2 g - Volume of HCl consumed = 30 cm³ (which is equivalent to 30 mL) - Normality of HCl = 1 N 2. **Use the Formula for Percentage of Nitrogen:** The formula to calculate the percentage of nitrogen in the organic compound is: \[ \text{Percentage of Nitrogen} = \frac{1.4 \times \text{Normality of HCl} \times \text{Volume of HCl (mL)}}{\text{Mass of organic compound (g)}} \] 3. **Substitute the Values into the Formula:** - Normality of HCl = 1 N - Volume of HCl = 30 mL - Mass of organic compound = 1.2 g Plugging these values into the formula: \[ \text{Percentage of Nitrogen} = \frac{1.4 \times 1 \times 30}{1.2} \] 4. **Calculate the Numerator:** \[ 1.4 \times 1 \times 30 = 42 \] 5. **Calculate the Percentage of Nitrogen:** \[ \text{Percentage of Nitrogen} = \frac{42}{1.2} = 35 \] 6. **Final Result:** The percentage of nitrogen in the organic compound is **35%**.
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