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The radius of Na^(+) is 95 pm and that o...

The radius of `Na^(+)` is 95 pm and that of `Cl^(-)`ions is 181 pm. Predict whether the coordination number of `Na^(+)` is 6 or4.

Text Solution

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Radius of `Na^(+) = 95 p m`
Radius of `Cl^(-) = 181 p m`
Radius ratio `(r_+)/(r_-) = (r(Na^+))/(r(Cl^-)) = 98/181 = 0.524`
The radius ratio lies between 0.414 - 0.723. Hence , `Na^(+)` ions prefer to occupy octahedral holes having coordination number 6.
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