Silver has atomic mass 108 a.m.u. and density `10.5 g cm^(-3)`. If the edge length of its unit cell is 409 pm, identify the type of unit cell. Also calculate the radius of an atom of silver.

Explanation

To solve the problem, we need to identify the type of unit cell for silver and calculate the radius of a silver atom. Here’s the step-by-step solution:

### Step 1: Identify the Type of Unit Cell
To determine the type of unit cell, we can use the formula for density:

\[ D = \frac{Z \cdot M}{A^3 \cdot N_0} \]
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