In solid, oxide ions are arranged in ccp. One sixth of the tetrahedral voids are occupied by the cations (A) while one third of the octahedral voids, are occupied by the cations (B). What is the formula of the compound ?

Answer

`PQO_3`

Explanation

Suppose the number of oxide ions = N
No. of octahedral voids = N
No. of tetrahedral voids = 2N
No. of cations P present = `1/6 xx 2N = 1/3 N`
No. of cations Q present = `1/3 xx N = N/3`
Ratio `P : Q : O^(2-)`
`N/3 : N/3 : N or 1 : 1 : 3 . `
Formula of compound = `PQO_3`.