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why is Fe0(s) not formed in stoichio...

why is ` Fe0(s)` not formed in stoichiometric compostion ?

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In the crystals of `FeO`, some of the `Fe^(2+)` cations are replaced by `Fe^(3+)` ions. To balance the charge, three `Fe^(2+` ions are replaced by two `Fe^(3+)` ions to make up for the loss of positive charge. As a result, there would be less amount of metal as compared to stoichiometric proportion.
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