Match the entries of column I with appropriate entries of column II.
`{:("Compound ","Magnetic property"),((A) NaCl , (p) " Ferrimagnetic"),((B) MnO , (q) " Paramagnetic"),((C) CrCl_3,(r) " Ferromagnetic"),((D)CrO_2, (s) " Diamagnetic"),((E)MgFe_2O_4,(t) " Antiferromagnetic"):}`

Options

A. `{:(P,Q,R,S),(4,1,3,2):}`
B. `{:(A,B,C,D,E),(t,q,r,p,s):}`
C. `{:(A,B,C,D,E),(r,t,q,p,s):}`
D. `{:(A,B,C,D,E),(s,t,q,r,p):}`

Answer

To solve the matching question, we need to identify the magnetic properties of each compound listed in Column I and match them with the appropriate entries in Column II. Here's the step-by-step solution:

### Step 1: Identify the magnetic properties of each compound.

1. **NaCl**:
- NaCl is an ionic compound composed of Na⁺ and Cl⁻ ions. It does not have unpaired electrons, which means it does not exhibit magnetism.
- **Magnetic Property**: Diamagnetic (s)

2. **MnO**:
- MnO contains manganese in the +2 oxidation state (Mn²⁺), which has unpaired electrons.
- **Magnetic Property**: Antiferromagnetic (t)

3. **CrCl₃**:
- CrCl₃ contains chromium in the +3 oxidation state (Cr³⁺), which has unpaired electrons.
- **Magnetic Property**: Paramagnetic (q)

4. **CrO₂**:
- CrO₂ contains chromium in the +4 oxidation state (Cr⁴⁺) and exhibits ferromagnetism due to the presence of unpaired electrons.
- **Magnetic Property**: Ferromagnetic (r)

5. **MgFe₂O₄**:
- MgFe₂O₄ is a spinel ferrite and exhibits ferrimagnetism due to the presence of both Fe²⁺ and Fe³⁺ ions, which have unpaired electrons.
- **Magnetic Property**: Ferrimagnetic (p)

### Step 2: Match the compounds with their magnetic properties.

Now we can summarize the matches as follows:

- **(A) NaCl** - (s) Diamagnetic
- **(B) MnO** - (t) Antiferromagnetic
- **(C) CrCl₃** - (q) Paramagnetic
- **(D) CrO₂** - (r) Ferromagnetic
- **(E) MgFe₂O₄** - (p) Ferrimagnetic

### Final Matches:
- (A) NaCl → (s) Diamagnetic
- (B) MnO → (t) Antiferromagnetic
- (C) CrCl₃ → (q) Paramagnetic
- (D) CrO₂ → (r) Ferromagnetic
- (E) MgFe₂O₄ → (p) Ferrimagnetic