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A metal 'X' crytallizes in a unit cell i...

A metal 'X' crytallizes in a unit cell in which the radius of atom (r) is related to edge of unit cell (a) as r = 0.3535 a. The total number of atoms present per unit cell is

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To find the total number of atoms present per unit cell (Z) for the metal 'X' that crystallizes in a unit cell with the given relation between the radius of the atom (r) and the edge length of the unit cell (a), we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Relationship**: We are given the relationship between the radius of the atom and the edge length of the unit cell: \[ r = 0.3535a \] 2. **Consider Possible Unit Cell Types**: There are three common types of unit cells: Simple Cubic (SCC), Body-Centered Cubic (BCC), and Face-Centered Cubic (FCC). Each has a different number of atoms per unit cell: - SCC: Z = 1 - BCC: Z = 2 - FCC: Z = 4 3. **Check for Simple Cubic (SCC)**: For a Simple Cubic structure, the relationship between r and a is: \[ a = 2r \] Substituting \(r = 0.3535a\) into the SCC equation: \[ a = 2(0.3535a) \implies a = 0.707a \] This is not possible, so it cannot be a Simple Cubic structure. 4. **Check for Body-Centered Cubic (BCC)**: For a Body-Centered Cubic structure, the relationship is: \[ 4r = \sqrt{3}a \] We can express this in terms of our given relationship: \[ 2r = \frac{\sqrt{3}}{2}a \] Substituting \(r = 0.3535a\): \[ 2(0.3535a) = \frac{\sqrt{3}}{2}a \implies 0.707a = 0.866a \] This is also not possible, so it cannot be a Body-Centered Cubic structure. 5. **Check for Face-Centered Cubic (FCC)**: For a Face-Centered Cubic structure, the relationship is: \[ 4r = \sqrt{2}a \] Substituting our relationship: \[ 4(0.3535a) = \sqrt{2}a \] Simplifying: \[ 1.414a = \sqrt{2}a \] Since both sides are equal, this confirms that the structure is indeed Face-Centered Cubic. 6. **Conclusion**: Since we have established that the metal 'X' crystallizes in a Face-Centered Cubic structure, the total number of atoms per unit cell (Z) is: \[ Z = 4 \] ### Final Answer: The total number of atoms present per unit cell is **4**.

To find the total number of atoms present per unit cell (Z) for the metal 'X' that crystallizes in a unit cell with the given relation between the radius of the atom (r) and the edge length of the unit cell (a), we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Relationship**: We are given the relationship between the radius of the atom and the edge length of the unit cell: \[ r = 0.3535a ...
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