In a coagulation experiment, `5mL` of `As_(2)S_(3)` is mixed with distilled water and `0.1M` solution of an electrolyte `AB` so that the total volume is `10mL` . It was found that all solutions sontianing more than `4.6mL` . Of `AB` coagulate within `5` min. What is the flocculation value of `AB` for `As_(2)S_(3)` solution?
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A minimum of 4.6 mL of AB electrolyte is required to coagulate the sol. 4.6 mL of 0.1M AB solution `=(0.1 xx 4.6)/(1000) = 4.6 xx10^(-4)` mole = 0.46 mmoles 10mL of colloidal solution reuire electrolyte AB for complete coagulation `=0.46` mmoles 1000 mL of colloidal solution requre electrolyte AB for complete coagulation `=0.46/10 xx 1000 = 46` mmoles `:.` Flocculation value of AB for `As_2S_3` sol = 46.
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