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Adsorption of a gas on the surface of so...

Adsorption of a gas on the surface of solid is sgenerally accompanied by decrease in entropy but still it is spontaneous in naturre. Explain.

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The molecules of adsorbate are held on the surface of adsorbent and therefore, they have lesser tendency to move freely. Therefore, its entropy decreases and `DeltaS` is -ve, which opposes the process. However, adsorption is an exothermic process and therefore, `DeltaH` is-ve. The magnitude of `DeltaH` is more than `T Delta S` so that
`DeltaG = DeltaH - T Delta S = (-) - T (-)`
if `DeltaH gt T Delta S, DeltaS = -ve`
Therefore, there is decrease in free energy and hence, it is a spontaneous process.
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