Home
Class 12
CHEMISTRY
In an adsorption experiment, a graph bet...

In an adsorption experiment, a graph between log `(x/m)` versus log `P` was found to be linear with a slope of `45^(@)` . The intercept on the log `(x/m)` axis was found to be `0.3010` . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of `0.5` atm` .

Text Solution

Verified by Experts

According to Freundlich adsorption isotherm,
`x/m = kp^(1//n)`
or `log""(x)/m =log k + 1/n logP`
Plot of `log""((x)/m)` vs log P is linear with slope `= 1/n` and intercept = log k . Thus,
Slope `= 1/n = tan 45^@ = 1`
`:.n = 1`
Intercept log k = 0.3010
or `k = 2`
`x/m = kP^(1//n)`
`= 2 xx(0.5)^1 = 1.0`
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    MODERN PUBLICATION|Exercise COMPETITION FILE (OBJECTIVE TYPE QUESTIONS) (A. MULTIPLE CHOICE QUESTIONS WITH ONLY ONE CORRECT ANSWER)|26 Videos

  • SURFACE CHEMISTRY

    MODERN PUBLICATION|Exercise COMPETITION FILE (OBJECTIVE TYPE QUESTIONS) (B. MULTIPLE CHOCE QUESTIONS FROM COMPETITIVE EXAMINATIONS)|49 Videos

  • SURFACE CHEMISTRY

    MODERN PUBLICATION|Exercise REVISION EXERCISE (LONG ANSWER QUESTIONS )|13 Videos

  • SOLUTIONS

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|14 Videos

Similar Questions

Explore conceptually related problems

In an adsorption experiment, a graph between log (x/m) versus log P was found to be linear with a slope of 45^(@) . The intercept on the log y axis was found to be 0.301 . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of 3.0 atm.

In an adsorption experiment a graph between log x/m versus log P was fond to be linear with a slope of 45^@) . The intercept on the log x/m axis was found to 0.70 . Calculate the amount of gas adsorbed per gram of charcoal under a pressure of 1 atm [log5=0.70]

In an Adsorption experiment a graph between log x//m versus log P was found to be linear with a slope of 45^(@) the intercept of the log x//m was found to be 0.3010 . Calculate the amount of gas adsorbed per gm of charcoal under a pressure of 0.6 bar.

A graph between log (x/m) and log p is straight line at an angle of 45^(@) with intercept on y-axis equal to 0.3010. Calculate the amount of the gas adsorbed per gram of the adsobent when the pressure is 0.2 atm.

When a graph is plotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y- axis . If initial pressure is 0.3 atm, what wil be the amount of gas adsorbed per gm of adsorbent :

When a graph is pplotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y-axis. If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent:

When a graph is plotted between log x//m and log p, it is striaght line with an angle 45^(@) and intercept 0.3010 on y-axis. If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent?