Complete the chemical equations :
`Cr_2O_7^(2-) + H_2S + H^(+) to `

Explanation

To complete the chemical equation \( \text{Cr}_2\text{O}_7^{2-} + \text{H}_2\text{S} + \text{H}^+ \), we need to follow these steps:

### Step 1: Identify the Oxidation and Reduction
- The dichromate ion \( \text{Cr}_2\text{O}_7^{2-} \) is a strong oxidizing agent. It will oxidize \( \text{H}_2\text{S} \) (where sulfur is in the -2 oxidation state) to elemental sulfur (where sulfur is in the 0 oxidation state).
- As \( \text{Cr}_2\text{O}_7^{2-} \) gets reduced, it will change from \( \text{Cr}_2\text{O}_7^{2-} \) to \( \text{Cr}^{3+} \).

### Step 2: Write the Half-Reactions
1. **Oxidation Half-Reaction**:
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