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Which out of the two La(OH)(3) and Lu(OH...

Which out of the two `La(OH)_(3) and Lu(OH)_(3)`, is more basic and why?

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`La(OH)_3` is more basic than `Lu(OH)_3` . Due to lanthanoid contraction the size of lanthanoid ions decreases regularly with increase in atomic size. As a result of decrease in size, their covalent character between lanthanoid ion and `OH^-` ions increases from `La^(3+)` to `Lu^(3+)` . Therefore, the basic character of hydroxides decreases from `La(OH)_3`to `Lu(OH)_3` .
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(a). Of the lanthanides, cerium (Z=58) forms a tetrapositive ion, Ce^(4+) in aqueous solution. Why? (b), The +3 oxidation states of lanthanum (Z=57) , gadolinium (Z=64) and lutetium (Z=71) are especially stable. Why? (c). Why Zr and or Nb anbd Ta exhibit similar properties ? (d). Which oiut of the two La(OH)_3 and Lu(OH)_3 , is more basic and why?

Why Ce(OH)_(3) is more basic than Lu(OH)_(3) ?

Lanthanoids and actinoids are f-block elements in which the last electron enters the anti-penultimate energy level. The most common oxidation state of lanthanoids is +3, though +2 and +4 oxidation states are exhibited by some of the elements. In lanthanoid series, there is a progressive decrease in atomic and ionic radii, known as lanthanoid contraction. Unlike lanthanoids, actinoids show a large number of oxidation states. Which out of La(OH)_3 and Lu(OH)_3 is more basic?

La^(3+) and Lu^(3+) are

Explain the following : (a) Out of Sc^(3+), Co^(2+) " and "Cr^(3+) "ions, only "Sc^(3+) is colourless in aqueous solutions. (Atomic no.: Co =27, Sc = 21 and Cr =24) (b) The E^(@)Cu^(2+)//Cu for copper metal is positive (+0.34), unlike the remaining members of the first transition series. (c) La(OH)_(3) " is more basic than Lu "(OH)_(3).

Among the lanthanides, La^(3+) and Lu^(3+) ions are