A compound has been found to have magnetic moment of 3.9 B.M. How many unpaired electrons does it contain ?

Explanation

To determine the number of unpaired electrons in a compound with a magnetic moment of 3.9 B.M., we can use the formula for magnetic moment:

\[ \mu = \sqrt{n(n + 2)} \]

where \( \mu \) is the magnetic moment in Bohr Magnetons (B.M.) and \( n \) is the number of unpaired electrons.

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