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How would you account for the following:...

How would you account for the following:
A) Of the `d^(4)` species `Cr^(2+)` is strongly reducing while manganese(III) is strongly oxidizing.
B) Cobalt(II) is stable in aqueous solution but in the presence of complexing reagents it is easily oxidized.
C) The `D^(1)` configuration is very unstable in ions.

Text Solution

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(a) E values for `Cr^(3+) | Cr^(2+)` is negative (-0.41 V) and for `Mn^(3+)| Mn^(2+)` is positive (+1.57 V). Thus, `Cr^(2+)` can undergo oxidation and, therefore, is reducing agent. On the other hand, Mn (III) can undergo reduction, and therefore, acts as an oxidizing agent.
(b) In the presence of complexing agents, cobalt gets oxidised from +2 to +3 state because Co (III) is more stable than Co (II).
(c) After loss of ns electrons, `d^1` electron can easily be lost to give a stable configuration. Therefore, the elements having `d^1` configuration are either reducing or undego disproportionation.
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How would you account for the following: of the d^(4) species Cr^(2+) is strongly reducing while manganese(III) is strongly oxiding. Cobalt(II) is stable in aqueous solution but in the presence of complexing reagents it is easily oxidised. The D^(1) configuration is very unstable in ions.

How will you account for the following : (i) Cobalt (II) is stable in aqueous solution but in the presence of a complexing agent, it is easily oxidized. (ii) Out of d^(4) species, Cr^(2+) is strongly reducing while Mn^(2+) is strongly oxidising .

(a) How would you account for the following : (i) Cobalt (II) is stable in aqueous solution but in the presence of strong ligands, it is easily oxidised. (ii) The transition metals form interstitial compounds. (iii) Silver halides find use in photography. (b) What is lanthanoid contraction ? Mention its main consequences.

Give reasons for the following: (i) Transition metals exhibit a wide range of oxidation states. (ii) Cobalt (II) is very stable in aqueous solutions but gets easily oxidised in the presence of strong ligands. (iii) Actinoids exhibit a greater range of oxidation states than lanthanoids.

How would you account for the following ? (i) With the same d-orbital configuration (d^(4)) Cr^(2+) is reducting agent while Mn^(3+) is an oxidizing agent. (ii) The actionoids exhibits a larger numbe of oxidation states than the corresponding members in the lanthanoid series. (iii) Most of the transition metal ions exhibit characteristic in colours in aqueous solutions.

MODERN PUBLICATION-D AND F-BLOCK ELEMENTS-NCERT FILE (TEXTBOOK EXERCISE)
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  2. Compare lanthanoids and actinoids with reference to : (i) the electr...

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  3. How would you account for the following: A) Of the d^(4) species Cr^(...

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  4. What is meant by 'disproportionation'? Give two examples of disproport...

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  5. Which metal in the first series of transition metals exhibits+1 oxidat...

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  6. Calculate the number of unpaired electrons in the following gaseous io...

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  7. Give examples and suggest reasons for the following features of the t...

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  8. Indicate the steps in the preparation of: (i). K2Cr2O7 from chromite...

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  9. What are alloys? Name an important alloy which contains some of the la...

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  10. What are inner-transition elements? Decide which of the following atom...

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  11. The chemistry of the actinoid elements is not so smooth as that of the...

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  12. Which is the last element in the series of the actinods? Write the ele...

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  13. Use Hund's rule to derive the electronic configuration of Ce^(3+) ion,...

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  14. Name the member of the lanthanoids series which exhibit+4 oxidation st...

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  15. Compare lanthanoids and actinoids with reference to : (i) the electr...

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  16. Write the electronic configuration of the elements with the atomic num...

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  17. Compare the general characteristics of the first series of the transit...

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  18. Write down the number of 3d electrons in each of the following ions : ...

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  19. Comments on the statement that elements of the first transition serie...

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  20. What can be inferred from the magnetic moment values of the following ...

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