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The element of first transition series w...

The element of first transition series which shows maximum number of oxidation states is

A

Mn

B

Cr

C

Fe

D

Cu

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To solve the question of which element of the first transition series shows the maximum number of oxidation states, we will analyze the oxidation states of manganese, chromium, iron, and copper step by step. ### Step 1: Identify the Elements and Their Electronic Configurations The first transition series includes the elements from Scandium (Sc) to Zinc (Zn). For this question, we will focus on: - Manganese (Mn) - Chromium (Cr) - Iron (Fe) - Copper (Cu) The atomic numbers and electronic configurations are as follows: - Manganese (Mn): Atomic number 25, Electronic configuration: [Ar] 3d^5 4s^2 - Chromium (Cr): Atomic number 24, Electronic configuration: [Ar] 3d^5 4s^1 (due to stability of half-filled d-orbitals) - Iron (Fe): Atomic number 26, Electronic configuration: [Ar] 3d^6 4s^2 - Copper (Cu): Atomic number 29, Electronic configuration: [Ar] 3d^{10} 4s^1 ### Step 2: Determine the Possible Oxidation States Next, we will determine the possible oxidation states for each element based on their electronic configurations. 1. **Manganese (Mn)**: - Can lose 2 electrons from 4s^2 and up to 5 electrons from 3d^5. - Possible oxidation states: +2, +3, +4, +5, +6, +7. - Total oxidation states = 6. 2. **Chromium (Cr)**: - Can lose 1 electron from 4s^1 and up to 5 electrons from 3d^5. - Possible oxidation states: +2, +3, +4, +5, +6. - Total oxidation states = 5. 3. **Iron (Fe)**: - Can lose 2 electrons from 4s^2 and up to 4 electrons from 3d^6. - Possible oxidation states: +2, +3, +4, +5, +6. - Total oxidation states = 5. 4. **Copper (Cu)**: - Can lose 1 electron from 4s^1 and up to 10 electrons from 3d^{10}. - Possible oxidation states: +1, +2, and occasionally +3, +4. - Total oxidation states = 4. ### Step 3: Compare the Oxidation States Now we compare the total number of oxidation states for each element: - Manganese: 6 oxidation states - Chromium: 5 oxidation states - Iron: 5 oxidation states - Copper: 4 oxidation states ### Conclusion The element of the first transition series that shows the maximum number of oxidation states is **Manganese (Mn)** with a total of 6 oxidation states. ### Final Answer **Manganese (Mn)**
To solve the question of which element of the first transition series shows the maximum number of oxidation states, we will analyze the oxidation states of manganese, chromium, iron, and copper step by step. ### Step 1: Identify the Elements and Their Electronic Configurations The first transition series includes the elements from Scandium (Sc) to Zinc (Zn). For this question, we will focus on: - Manganese (Mn) - Chromium (Cr) - Iron (Fe) - Copper (Cu) ...
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Which of the following shows maximum number of oxidation states :-

The elements of 3d transition series are given as : Sc Ti V Cr Mn Fe Co Ni Cu Zn Answer the following : (i) Write the element which shows maximum number of oxidation states. Give reason. (ii) Which elements has the highest m.p? (iii) Which element is a strong oxidizing agent in +3 oxidation state and why ?

The element with maximum number of oxidation states in their compounds is

The transition element ( with few exceptions ) show a large number of oxidation states . The various oxidation states are related to the electronic configuration of their atoms. The variable oxidation states of a transition metal is due to the involvement of (n-1)d and outer ns electrons . For the first five elements of 3d transition series , the minimum oxidation state is equal to the number of electrons in 4s shell and the maximum oxidation state is equal to the sum of 4s and 3d electrons. The relative stability of various oxidation states of a given element can be explained on the basis of stability of d^(0),d^(5) and d^(10) configuration . In 3d series, the maximum oxidation state is shown by

The transition element ( with few exceptions ) show a large number of oxidation states . The various oxidation states are related to the electronic configuration of their atoms. The variable oxidation states of a transition metal is due to the involvement of (n-1)d and outer ns electrons . For the first five elements of 3d transition series , the minimum oxidation state is equal to the number of electrons in 4s shell and the maximum oxidation state is equal to the sum of 4s and 3d electrons. The relative stability of various oxidation states of a given element can be explained on the basis of stability of d^(0),d^(5) and d^(10) configuration . In which of the following pairs , the first species is more stable than second one

Knowledge Check

  • The element in the first transition series that exhibits maximum number of oxidation states is

    A
    titanium.
    B
    zinc.
    C
    chromium.
    D
    manganese.

  • Which of the following shows maximum number of oxidation states :-

    A
    Cr
    B
    Fe
    C
    Mn
    D
    V

  • Out of the following transition elements, the maximum number of oxidation states are shown by

    A
    `Sc (Z=21)`
    B
    `Cr(Z=24)`
    C
    `Mn(Z=25)`
    D
    `Fe(Z=26)`