Maximum oxidation number of manganese is in

Options

A. `K_2MnO_4`
B. `MnO_2`
C. `KMnO_4`
D. `Mn_2O_4`

Explanation

To determine the maximum oxidation number of manganese, we can analyze its compounds and calculate the oxidation state step by step.

### Step 1: Understand the oxidation states
The oxidation state of an element in a compound can be determined by considering the charges of the other elements in the compound. Manganese (Mn) can exhibit various oxidation states, but we are interested in finding its maximum oxidation state.

### Step 2: Consider common compounds of manganese
Manganese commonly forms compounds with oxygen and alkali metals like potassium (K). A well-known compound is potassium permanganate (KMnO₄).

### Step 3: Set up the equation for KMnO₄
In KMnO₄:
- Potassium (K) has an oxidation state of +1.
- Oxygen (O) typically has an oxidation state of -2. Since there are 4 oxygen atoms, the total contribution from oxygen is 4 × (-2) = -8.

Let the oxidation state of manganese be represented as \( x \).

### Step 4: Write the charge balance equation
The compound is neutral, so the sum of the oxidation states must equal zero:
\[ +1 (from K) + x (from Mn) + (-8) (from O) = 0 \]

### Step 5: Solve for \( x \)
Rearranging the equation gives:
\[ x - 7 = 0 \]
\[ x = +7 \]

### Step 6: Conclusion
The maximum oxidation number of manganese in potassium permanganate (KMnO₄) is +7.

### Summary
The maximum oxidation number of manganese is +7, which occurs in compounds like KMnO₄.

---