Electronic configuration of `Fe^(2+)` ion is

Options

A. `[Ar]4s^(2) 3d^4`
B. `[Ar]4s^(1) 3d^5`
C. `[Ar] 3d^6`
D. `[Ar]3d^8`

Explanation

To find the electronic configuration of the `Fe^(2+)` ion, we will follow these steps:

### Step 1: Determine the electronic configuration of neutral iron (Fe).
- Iron (Fe) has an atomic number of 26.
- The electronic configuration of Fe is:
- 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶
- This can be abbreviated using the nearest noble gas (Argon, Ar) as:
- [Ar] 4s² 3d⁶

### Step 2: Understand the ionization process to form `Fe^(2+)`.
- To form the `Fe^(2+)` ion, we need to remove 2 electrons from the neutral iron atom.
- Electrons are removed from the outermost shell first. In this case, the outermost electrons are in the 4s orbital.

### Step 3: Remove the electrons.
- We remove the 2 electrons from the 4s orbital:
- From [Ar] 4s² 3d⁶, removing 2 electrons from 4s gives us:
- [Ar] 3d⁶

### Step 4: Write the final electronic configuration for `Fe^(2+)`.
- The electronic configuration of `Fe^(2+)` is:
- [Ar] 3d⁶

### Conclusion:
The electronic configuration of the `Fe^(2+)` ion is [Ar] 3d⁶.

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