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Increasing order of paramagnetism is...

Increasing order of paramagnetism is

A

`Cu^(2+) , Co^(2+) , Mn^(2+) , Ni^(2+)`

B

`Co^(2+) , Cu^(2+) , Mn^(2+) , Ni^(2+)`

C

`Cu^(2+) , Ni^(2+) , Co^(2+) , Mn^(2+) `

D

`Mn^(2+) , Co^(2+) , Ni^(2+) , Cu^(2+)`

Text Solution

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The correct Answer is:
To determine the increasing order of paramagnetism for the given transition metal ions (Cu²⁺, Co²⁺, Mn²⁺, and Ni²⁺), we need to analyze the number of unpaired electrons in each ion. The more unpaired electrons an ion has, the stronger its paramagnetic character. ### Step-by-Step Solution: 1. **Identify the transition metal ions and their electronic configurations:** - **Copper (Cu)**: Atomic number = 29 - Electronic configuration: \( \text{[Ar]} \, 3d^{10} \, 4s^1 \) - For \( \text{Cu}^{2+} \): \( \text{[Ar]} \, 3d^9 \, 4s^0 \) (1 unpaired electron) - **Cobalt (Co)**: Atomic number = 27 - Electronic configuration: \( \text{[Ar]} \, 3d^7 \, 4s^2 \) - For \( \text{Co}^{2+} \): \( \text{[Ar]} \, 3d^7 \, 4s^0 \) (3 unpaired electrons) - **Manganese (Mn)**: Atomic number = 25 - Electronic configuration: \( \text{[Ar]} \, 3d^5 \, 4s^2 \) - For \( \text{Mn}^{2+} \): \( \text{[Ar]} \, 3d^5 \, 4s^0 \) (5 unpaired electrons) - **Nickel (Ni)**: Atomic number = 28 - Electronic configuration: \( \text{[Ar]} \, 3d^8 \, 4s^2 \) - For \( \text{Ni}^{2+} \): \( \text{[Ar]} \, 3d^8 \, 4s^0 \) (2 unpaired electrons) 2. **Count the number of unpaired electrons for each ion:** - \( \text{Cu}^{2+} \): 1 unpaired electron - \( \text{Co}^{2+} \): 3 unpaired electrons - \( \text{Mn}^{2+} \): 5 unpaired electrons - \( \text{Ni}^{2+} \): 2 unpaired electrons 3. **Rank the ions based on the number of unpaired electrons:** - **Lowest paramagnetism**: \( \text{Cu}^{2+} \) (1 unpaired electron) - **Next**: \( \text{Ni}^{2+} \) (2 unpaired electrons) - **Next**: \( \text{Co}^{2+} \) (3 unpaired electrons) - **Highest paramagnetism**: \( \text{Mn}^{2+} \) (5 unpaired electrons) 4. **Write the increasing order of paramagnetism:** - \( \text{Cu}^{2+} < \text{Ni}^{2+} < \text{Co}^{2+} < \text{Mn}^{2+} \) ### Final Answer: The increasing order of paramagnetism is: \[ \text{Cu}^{2+} < \text{Ni}^{2+} < \text{Co}^{2+} < \text{Mn}^{2+} \]

To determine the increasing order of paramagnetism for the given transition metal ions (Cu²⁺, Co²⁺, Mn²⁺, and Ni²⁺), we need to analyze the number of unpaired electrons in each ion. The more unpaired electrons an ion has, the stronger its paramagnetic character. ### Step-by-Step Solution: 1. **Identify the transition metal ions and their electronic configurations:** - **Copper (Cu)**: Atomic number = 29 - Electronic configuration: \( \text{[Ar]} \, 3d^{10} \, 4s^1 \) - For \( \text{Cu}^{2+} \): \( \text{[Ar]} \, 3d^9 \, 4s^0 \) (1 unpaired electron) ...
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