Which of the following titanium compounds cannot be prepared ? (Atomic No. of Ti = 22)

Options

A. `TiO`
B. `TiO_2`
C. `K_2TiO_4`
D. `TiCl_2`

Explanation

To determine which titanium compound cannot be prepared, we need to analyze the oxidation states of titanium in each of the given compounds. The compounds in question are:

1. TiO
2. TiO2
3. K2TiO4
4. TiCl2

**Step 1: Analyze the oxidation states of titanium in each compound.**

1. **TiO**: In this compound, oxygen has an oxidation state of -2. Therefore, to balance this, titanium must have an oxidation state of +2. This is possible.

2. **TiO2**: Here, oxygen has an oxidation state of -2 (for two oxygen atoms, it totals -4). To balance this, titanium must have an oxidation state of +4. This is also possible.

3. **K2TiO4**: In this compound, potassium (K) has an oxidation state of +1 (for two potassium atoms, it totals +2). Oxygen has an oxidation state of -2 (for four oxygen atoms, it totals -8). Therefore, to balance this, titanium must have an oxidation state of +6. This oxidation state is not stable for titanium, as titanium typically does not exhibit a +6 oxidation state.

4. **TiCl2**: In this compound, chlorine has an oxidation state of -1 (for two chlorine atoms, it totals -2). Therefore, titanium must have an oxidation state of +2 to balance this. This is possible.

**Step 2: Conclusion**

From the analysis, we can conclude that the compound **K2TiO4** cannot be prepared because titanium does not exhibit a +6 oxidation state.

**Final Answer**: K2TiO4 cannot be prepared.

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