Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II and assign the correct code :

Answer

A

Explanation

`Co^(3+) : [Ar]3d^6`
No. of unpaired electrons = 4
spin magnetic moment `mu = sqrt(4(4+2)) = sqrt 24 B.M`
`Cr^(3+) : [Ar]3d^3`
No. of unpaired electron = 3
`mu = sqrt(3 (3+2)) = sqrt15 B.M`
`Fe^(3+) : [Ar] 3d^5`
no. of unpaired electrons = 5
`mu = sqrt(5(5+2)) =sqrt35 B.M`
`Ni^(2+) : [Ar]3d^8`
No. of unpaired electrons = 2
`mu = sqrt(2(2+2)) = sqrt8 B.M`
so ,correct option is A - (iv) , B - (v) , C - (ii) , D - (i)