` KMnO_4` gets reduced to

Options

A. `K_2MnO_4` in neutral medium
B. `MnO_2` in acidic medium
C. `Mn^(2+)` in alkaline medium
D. `MnO_2` in neutral medium

Explanation

To determine what KMnO4 gets reduced to in different mediums, we can analyze the reduction reactions of potassium permanganate (KMnO4) in neutral, acidic, and alkaline conditions.

### Step-by-Step Solution:

1. **Identify the Medium**: We need to consider the different mediums: neutral, acidic, and alkaline.

2. **Reduction in Neutral Medium**:
- In neutral medium, KMnO4 reacts with water.
- The reaction can be represented as:
\[ 2 KMnO_4 + 2 H_2O \rightarrow 2 KOH + 2 MnO_2 + 3 O \]
- Here, KMnO4 is reduced to MnO2.

3. **Reduction in Acidic Medium**:
- In acidic medium, KMnO4 is reduced to Mn2+.
- The reaction can be represented as:
\[ 2 KMnO_4 + 8 H^+ + 5 e^- \rightarrow 2 Mn^{2+} + 4 H_2O \]
- The oxidation state of manganese changes from +7 in KMnO4 to +2 in Mn2+.

4. **Reduction in Alkaline Medium**:
- In alkaline medium, KMnO4 is reduced to K2MnO4.
- The reaction can be represented as:
\[ 2 KMnO_4 + 2 KOH + H_2O \rightarrow 2 K_2MnO_4 + 3 O \]
- Here, the oxidation state of manganese changes from +7 to +6.

5. **Conclusion**:
- In neutral medium, KMnO4 is reduced to MnO2.
- In acidic medium, it is reduced to Mn2+.
- In alkaline medium, it is reduced to K2MnO4.
- Therefore, the answer to the question "KMnO4 gets reduced to" in neutral medium is **MnO2**.

### Final Answer:
**KMnO4 gets reduced to MnO2 in neutral medium.**