When `H_(2)O_(2)` is shaken with an acidified solution of `K_(2)Cr_(2)O_(7)` in the presence of ether , the ethereal layer turns blue due to the formation of

Options

A. `Cr_2O_3`
B. `CrO_4^(2-)`
C. `Cr_2(SO_4)_3`
D. `CrO_5`

Answer

D

Explanation

Acidified `K_2Cr_2O_7` solution reacts with hydrogen peroxide to give a deep blue solution due to the formation of peroxo compound, `CrO_5`
`K_2Cr_2O_7 + H_2SO_4 + 4H_2O_2 to 2CrO_5 + K_2SO_4 + 5H_2O`