Which one of the following ions has same numbr of unpaired electrons as those present in `V^(+3)` ions?

Options

A. `Ti^(3+)`
B. `Fe^(2+)`
C. `Ni^(2+)`
D. `Cr^(3+)`

Answer

C

Explanation

`V^(3+) (Z=23): 3d^2` Unpaired electrons = 2.
Number of unpaired electrons in `Ti^(3+) : 3d^1 (1), Fe^(3+) : 3d^5 (5), Ni^(2+) : 3d^8(2), Cr^(3+) : 3d^3 (3), Mn^(2+) : 3d^5(5)` .
Therefore, `Ni^(2+)` has same number of unpaired electrons as `V^(3+)`