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Incorrect statement with reference to Ce...

Incorrect statement with reference to Ce (Z = 58).

A

`Ce^(4+)` is a reducing agent.

B

Ce in +3 oxidation state is more stable than in +4.

C

Atomic size of Ce is more than that of Lu.

D

Ce shows common oxidation states of +3 and +4.

Text Solution

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The correct Answer is:
To determine the incorrect statement regarding Cerium (Ce, Z = 58), we will analyze the provided options step by step. ### Step 1: Understand the Electronic Configuration of Cerium - The atomic number of Cerium (Ce) is 58. Its electronic configuration can be written as: \[ \text{Ce: } [Xe] 4f^1 5d^1 6s^2 \] - This configuration indicates that Cerium has electrons in the 4f, 5d, and 6s subshells. ### Step 2: Analyze the Electronic Configuration of Ce^4+ - When Cerium loses four electrons to form Ce^4+, the electronic configuration changes as follows: - Two electrons are removed from the 6s subshell. - One electron is removed from the 5d subshell. - One electron is removed from the 4f subshell. Thus, the electronic configuration of Ce^4+ is: \[ \text{Ce}^{4+}: [Xe] 4f^0 5d^0 6s^0 \] - This indicates that Ce^4+ has achieved a noble gas configuration. ### Step 3: Determine the Nature of Ce^4+ - A reducing agent is a species that can be oxidized further, meaning it can lose more electrons. - Since Ce^4+ has reached a noble gas configuration, it cannot lose any more electrons to form Ce^5+. Therefore, it cannot act as a reducing agent. - Thus, the statement "Ce^4+ is a reducing agent" is incorrect. ### Step 4: Evaluate Other Options - **Option B:** "Ce^3+ oxidation state is more stable than Ce^4+." - This is correct because the energy required to remove three electrons (to form Ce^3+) is less than that required to remove four electrons (to form Ce^4+). - **Option C:** "Atomic size of Ce is more than that of Lu." - This is also correct due to lanthanide contraction, where the atomic size decreases as the atomic number increases in the lanthanide series. - **Option D:** "Ce shows common oxidation states of +3 and +4." - This is correct as well; Ce commonly exhibits +3 and +4 oxidation states. ### Conclusion After analyzing all options, the incorrect statement is: - **A:** "Ce^4+ is a reducing agent." ### Final Answer The incorrect statement with reference to Ce (Z = 58) is: - **A:** "Ce^4+ is a reducing agent." ---

To determine the incorrect statement regarding Cerium (Ce, Z = 58), we will analyze the provided options step by step. ### Step 1: Understand the Electronic Configuration of Cerium - The atomic number of Cerium (Ce) is 58. Its electronic configuration can be written as: \[ \text{Ce: } [Xe] 4f^1 5d^1 6s^2 \] - This configuration indicates that Cerium has electrons in the 4f, 5d, and 6s subshells. ...
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MODERN PUBLICATION-D AND F-BLOCK ELEMENTS-COMPETITION FILE (MULTIPLE CHOICE QUESTION ((B) MULTIPLE CHOICE QUESTION FROM COMPETITIVE EXAMINATION))
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  3. Incorrect statement with reference to Ce (Z = 58).

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  14. The effect of lanthanoid contraction in the lanthanoid series of eleme...

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