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In a finite G.P. the product of the term...

In a finite G.P. the product of the terms equidistant from the beginning and the end is always same and equal to the product of first and last term.

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The correct Answer is:
`=a_(1)a_(n)`, which is true.
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(iv) In a finite GP the product of the terms equidistant from the beginning and end is always same and is equal to the product of first and last term.

Statement -1: If a_(1),a_(2),a_(3), . . . . .,a_(n), . . . is an A.P. such that a_(1)+a_(4)+a_(7)+ . . . .+a_(16)=147 , then a_(1)+a_(6)+a_(11)=98 Statement -2: In an A.P., the sum of the terms equidistant from the beginning and the end is always same and is equal to the sum of first and last term.

Show that in an A.P.the sum of the terms equidistant from the beginning and end is always same and equal to the sum of first and last terms.

In the expansion of (1+x)^(n) the coefficients of terms equidistant from the beginning and the end are equal.

In a G.P 5 th term is 4 , then what is the product of first 9 terms of same G.P.is

Prove that in any arithmetic progression , whose common difference is not equal to zero, the product of two terms equidistant from the extreme terms is the greater as it will move to the middle term .

If the product of 4 terms of a G.P. is 729 , then find the GM of the G.P.

If the sixth term of a GP be 2, then the product of first eleven terms is

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