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19th term of the sequencea(n)=(n-2)/(n+3...

19th term of the sequence`a(n)=(n-2)/(n+3)` is…………….

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To find the 19th term of the sequence defined by the formula \( a(n) = \frac{n - 2}{n + 3} \), we will follow these steps: ### Step-by-Step Solution: 1. **Identify the term to find**: We need to find the 19th term, which means we will substitute \( n = 19 \) into the formula. 2. **Substitute \( n \) into the formula**: \[ a(19) = \frac{19 - 2}{19 + 3} \] 3. **Calculate the numerator**: \[ 19 - 2 = 17 \] 4. **Calculate the denominator**: \[ 19 + 3 = 22 \] 5. **Combine the results**: \[ a(19) = \frac{17}{22} \] 6. **Final answer**: The 19th term of the sequence is \[ \frac{17}{22} \]
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