If `theta_1,theta_2,theta_3, ,theta_n` are in AP, whose common difference is `d` , show that `sectheta_1s e ctheta_2+s e ctheta_2sectheta_3++sectheta_(n-1)sectheta_n=(t a ntheta_n-t a ntheta_1//)/(sind)`

If theta_(1),theta_(2),theta_(3),theta_(n) are in AP,whose common difference is d, show that sec theta_(1)sec theta_(2)+sec theta_(2)sec theta_(3)+....+sec theta_(n-1)sec theta_(n)=(tan theta_(n)-tan theta_(1))/(sin d)

If theta_(1),theta_(2),theta_(3),".......",theta_(n) are in AP whose common difference is d, then show that sind{sectheta_(1) sectheta_(2)+ sectheta_(2)sectheta_(3)+"........"+sectheta_(n-1)sectheta_(n)}=tantheta_(n)-tantheta_(1) .

Prove that: sectheta sec 2theta+sec2thetasec3theta+sec3theta.sec4theta+…to n terms = 1/(sintheta) [tan(n+1)theta-tantheta]

If : sectheta+costheta=2 "then" : sec^(2)theta-sec^(4)theta=

If cosectheta-sintheta=m" and " sectheta-costheta=n , elimnate theta .

if theta_1, theta_2, theta_3, ........, theta_n are in AP then (sintheta_1 + sintheta_2 + ....... + sintheta_n) / (costheta_1 + costheta_2 + costheta_3 + ...... + costheta_n ) =?

If theta_(1),theta_(2),theta_(3)....,theta_(n) are in A.P. then (sin theta_(1)+sin theta_(2)+...+sin theta_(n))/(cos theta_(1)+cos theta_(2)+...+cos theta_(n))=

Prove that : (tan theta)/(sectheta+1)-(tantheta)/(1-sectheta)=2cosec theta