A car travels from X to Y at a speed of 50km/h and returns back from Y to X at a speed of 60km/h Find the average speed and velocity of the car.

Explanation

Let x be the distance between X and Y. time taken by the car to travel from X to Y is.
`t_(1)=(x)/(50)`
Time taken by the car to travel From Y to X is
`t_(2)=(x)/(60)`
Total time taken by the car to travel from X to Y and then Y to X is
`t_(2)+t_(2)=(x)/(50)+(x)/(60)=x((1)/(50)+(1)/(60))=(11x)/(300)s`
Total distance covered in the journey =2x
`therefore` Average speed `=((2x)/(11x))/(300)(300xx2)/(11)=(600)/(11)` m/s
`=54.55` m/s
In the total journey, the car started from point X and returns back to X, so, the net displacement of the car is zero
`therefore` Average velocity =0