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The displacement x of a particle varies ...

The displacement x of a particle varies as
`sqrt(x)=t-2`
(i) What is the velocity and acceleration of the particle at t=0?
(ii) When will the velocity of the particle become zero?
(iii) What is the displacement of the particle when its velocity is zero?
(iv) Is the motion of the particle uniformly accelerated or not?

Text Solution

AI Generated Solution

To solve the problem step by step, we start with the given displacement function and derive the necessary quantities. ### Step 1: Rewrite the displacement function The displacement \( x \) of the particle is given by: \[ \sqrt{x} = t - 2 \] Squaring both sides, we get: ...
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Knowledge Check

  • The motion of a particle is described as s = 2-3t + 4t^(3) . What is the acceleration of the particle at the point where its velocity is zero?

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    A)0
    B
    B)4
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    D
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  • If v = x^2 - 5x + 4 , find the acceleration of the particle when velocity of the particle is zero.

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    3
    D
    none of these
  • If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the velocity of particle at t=2 is

    A
    `-9" units/sec"`
    B
    9 units/sec
    C
    `-18" units/sec"`
    D
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