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An electron enters an electric field of ...

An electron enters an electric field of width 40`mu` m with a speed of `6xx10^(3)m//s` and takes 6ns to cross it. Find its acceleration and velocity just after it exists the field.

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To solve the problem step by step, we will follow the physics principles related to motion in a straight line under constant acceleration. ### Given Data: - Width of the electric field (S) = 40 µm = 40 × 10^(-6) m = 4 × 10^(-5) m - Initial speed of the electron (U) = 6 × 10^3 m/s - Time taken to cross the field (T) = 6 ns = 6 × 10^(-9) s ### Step 1: Calculate the acceleration (A) ...
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