Home
Class 11
PHYSICS
A truck starts from rest and accelerates...

A truck starts from rest and accelerates uniformly to a velocity of 40m/s in 10s, it then runs with this uniform velocity and is finally brought to rest in 50m by a uniform deceleration. If the total run of the truck is 500m, find its acceleration and total time of journey.

Text Solution

AI Generated Solution

To solve the problem step by step, we will break down the truck's journey into three parts: acceleration, constant velocity, and deceleration. ### Step 1: Calculate the acceleration during the first part of the journey. The truck starts from rest and accelerates uniformly to a velocity of 40 m/s in 10 seconds. - **Initial velocity (u)** = 0 m/s (since it starts from rest) - **Final velocity (v)** = 40 m/s ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS|28 Videos
  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise CONCEPTUAL QUESTIONS|14 Videos
  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise Chapter Practice Test|15 Videos
  • OSCILLATIONS

    MODERN PUBLICATION|Exercise Practice Test (For Board Examination)|12 Videos

Similar Questions

Explore conceptually related problems

A car starts from rest and accelerates uniformly for 20 seconds to a velocity of 72 km h^(–1) . It then runs at constant velocity and finally brought to rest in 200 m with a constant retardation. The total distance covered is 600 m. Find the acceleration, retardation and the total time taken.

An automobile starts from rest and accelerates unifomly for 30 second to a speed of 72 km h^(-1) . It then moves with a uniform veocit and it is finally brought to rest in 50 m with a constant retardation. If the total distance travelled is 950 m , find the accleration, the retaradation and total time taken.

A motor car starts from rest and accelerates uniformly for 10 s to a velocity of 20 ms^(-1) . It then runs at a constant speed and is finally brought to rest in 40 m with a constant acceleration. Total distance covered is 640 m. Find the value of acceleration, retardation and total tie taken.

A car starts form rest and accelerates uniformly for 10 s to a velocity of 8 ms ^(-1) . It then runs at a constant velocity an dis finally brought to rest in 64 m with a constant retardation. The totla distance covered by the car is 584 m Find the value of acceleration, retardation, and totl time taken.

A motor car, starting from rest, moves with uniform acceleration and attains a velocity of 8 ms^(-1) in 8 s. It then moves with uniform velocity and finally brought to rest in 32 m under unifrom retardation. The total distance covered by the car is 464 m. Find the total time taken.

A motor car, starting from rest, moves with uniform acceleration and attains a velocity of 8 ms^(-1) in 8 s. It then moves with uniform velocity and finally brought to rest in 32 m under unifrom retardation. The total distance covered by the car is 464 m. Find the acceleration.

A motor car, starting from rest, moves with uniform acceleration and attains a velocity of 8 ms^(-1) in 8 s. It then moves with uniform velocity and finally brought to rest in 32 m under unifrom retardation. The total distance covered by the car is 464 m. Find the retardation

A motor car starts from rest and accelerates uniformly for 10 s to a velocity of 30 ms^(-1) . It then runs at a constant speed and is finally brought to distance covered is 830 m . Find the value of acceleration, retardation and total time taken.

Starting from rest a car moves with uniform acceleration and attains a velocity of 72 kmh^(-1) in 15 s. It then moves with uniform speed for 20s and is then brought to rest in 10 s undere uniform retardation. Find total distance travelled using velocity - time graph.