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A body covers a distance of 15 m in the ...

A body covers a distance of 15 m in the 5th second and 20m in the 7th How much it will cover in the 12th second?

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To solve the problem of how much distance a body will cover in the 12th second, given that it covers 15 m in the 5th second and 20 m in the 7th second, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Formula**: The distance covered by a body in the nth second can be calculated using the formula: \[ S_n = u + \frac{a}{2} (2n - 1) ...
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Knowledge Check

  • A body of mass 3kg moving with a constant acceleration covers a distance of 10m in the 3rd second and lbm in the 4th ssecond respectively. The initial velocity of the body is

    A
    `10ms^(-1)`
    B
    `8ms^(-1)`
    C
    `5ms^(-1)`
    D
    `-5ms^(-1)`

  • A body moving with a uniform acceleration crosses a distance of 15 m in the 3^(rd) second and 23 m in the 5^(th) second. The displacement in 10 s will be

    A
    `150 m`
    B
    `200 m`
    C
    `250 m`
    D
    `300 m`

  • A body of mass 3 kg moving with a constant acceleration covers a distance of 10 m in the 3^(rd) second and 16 m in the 4^(th) second respectively. The initial velocity of the body is

    A
    `10ms^(-1)`
    B
    `8ms^(-1)`
    C
    `5ms^(-1)`
    D
    `-5ms^(-1)`

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    A body covers 12m in 2nd second and 20m in 4th second. How much distance will it cover in 4 seconds after the 5th second ?

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