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A boy projects a stone vertically upward...

A boy projects a stone vertically upwards and catches it back after 5s. How high the stone goes and with what velocity it was thrown? Also calculate the separation between the highest point and the stone 4 s after it was projected upwards.
Take g=10 `m//s^(2)`

Text Solution

AI Generated Solution

To solve the problem step by step, we will break it down into three parts as outlined in the question: 1. **Determine the initial velocity (u) of the stone.** 2. **Calculate the maximum height (h) the stone reaches.** 3. **Find the separation between the highest point and the stone 4 seconds after it was projected.** ### Step 1: Determine the Initial Velocity (u) ...
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Knowledge Check

  • A stone is project vertically upward from the top of a tower of height 60 m. The stone moves according to the law S=(10)t-5t^(2) , where S is in meters and t in second The maximum height , reached by the stone , from the ground , is

    A
    60 m
    B
    55 m
    C
    65 m
    D
    50 m

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