Home
Class 11
PHYSICS
From the adjoining acceleration-time gra...

From the adjoining acceleration-time graph for a particle, find the average acceleration in initial 30s.

Text Solution

Verified by Experts

`25m//s^(2)`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise CONCEPTUAL QUESTIONS|14 Videos

  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise TOUGH & TRICKY ( PROBLEMS)|10 Videos

  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|16 Videos

  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise Chapter Practice Test|15 Videos

  • OSCILLATIONS

    MODERN PUBLICATION|Exercise Practice Test (For Board Examination)|12 Videos

Similar Questions

Explore conceptually related problems

Fig. 3.39 shows the acceleration - time graph for a particle in rectilinear motion. Find the average acceleration in first 20 s.

Fig. 2 (b) .16 shows the time-acceleration graph for a particle in rectillinear motion. Find the averate acceleration in first twenty seconds. .

The adjoining curve represents the velocity-time graph of a particle, its acceleration values along OA, AB and BC in metre/sec2 are respectively-

The graph between displacement and time for a particle moving with uniform acceleration is a

Acceleration time graph of a particle moving along a straight line is given. Then average acceleration between t=0 & t=4 is :-

The acceleration - time graph for a particle moving along x - axis is shown in figure, If the initial velocity of particle is -5m//s , the velocity at t = 8 s is

Figure shows the acceleration-time graph of a particle moving along a straight line. After what time the particle acquires its initial velocity?

The acceleration versus time graph for a particle moving along a straight line is shown in the figure. If the particle starts from rest at t = 0, then its speed at t = 30 sec will be :

MODERN PUBLICATION-MOTION IN A STRAIGHT LINE -PRACTICE PROBLEMS
  1. A car is travelling along a straight line and covers one-fourth of the...

    Text Solution

    |

  2. Calculate the displacement and distance travelled by the body in 5 s, ...

    Text Solution

    |

  3. From the adjoining acceleration-time graph for a particle, find the av...

    Text Solution

    |

  4. Calculate the displacement covered by a moving body in 8s. The velocit...

    Text Solution

    |

  5. A body is projected in a vertical direction. The altitude y is given b...

    Text Solution

    |

  6. The displacement of a particle moving along a straight line is given b...

    Text Solution

    |

  7. A particle is moving with an intial velocity of 5ms^(-1). What will be...

    Text Solution

    |

  8. The velocity of an object varies as v=h(t^(2))/(4). Calculate the chan...

    Text Solution

    |

  9. A particle is moving with an initial velocity of 2m/s and covers a dis...

    Text Solution

    |

  10. A particle is moving under a constant acceleration of 3m//s^(2). The i...

    Text Solution

    |

  11. A particle moves 20m in 3rd second and 30m in 5th second of its journe...

    Text Solution

    |

  12. A particle is initially at rest. It starts moving with a constant acce...

    Text Solution

    |

  13. What will be the minimum stopping distance required by a car to stop i...

    Text Solution

    |

  14. A ball is thrown vertically upwards from ground with such a speed so t...

    Text Solution

    |

  15. A ball A is dropped from the top of a tower 500m high and at the same ...

    Text Solution

    |

  16. Two bodies are dropped from two different building, one at a height 20...

    Text Solution

    |

  17. Two balls are released from the same height at an interval of 2s. When...

    Text Solution

    |

  18. A bus A travelling at a speed of 70 km/h just overtakes another bus B ...

    Text Solution

    |

  19. A boy starts running on a straight line path with speed of 20km/h star...

    Text Solution

    |

  20. Two trains A and B each of length 200m are running on parallel tracks....

    Text Solution

    |