A particle is moving with an intial velocity of `5ms^(-1)`. What will be the velocity of the particle at t=3s, if the acceleration of the particle is given by
`a=16t^(3)-12t^(2)+6t-25`

Explanation

To find the velocity of a particle at \( t = 3 \) seconds given its initial velocity and a time-dependent acceleration function, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Information**:
- Initial velocity \( u = 5 \, \text{m/s} \)
- Acceleration \( a(t) = 16t^3 - 12t^2 + 6t - 25 \)

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