A particle moves 20m in 3rd second and 30m in 5th second of its journey what will be the distance covered by the body in 4s after 6th second?

Explanation

To solve the problem step by step, we need to determine the distance covered by a particle in the 4 seconds after the 6th second, given that it travels 20 m in the 3rd second and 30 m in the 5th second.

### Step 1: Understand the distance traveled in nth second
The distance traveled by a particle in the nth second can be expressed as:
\[ s_n = u + \frac{a}{2}(2n - 1) \]
where \(s_n\) is the distance traveled in the nth second, \(u\) is the initial velocity, \(a\) is the acceleration, and \(n\) is the second.
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