A ball A is dropped from the top of a tower 500m high and at the same instant another ball b is projected upwards with the velocity of 100m/s. after how much time and where the two balls will meet?

Explanation

To solve the problem of two balls, A and B, one dropped from the top of a 500 m tower and the other projected upwards with a velocity of 100 m/s, we can follow these steps:

### Step 1: Identify the motion of both balls
- **Ball A** is dropped from the top of the tower. Its initial velocity (u_A) is 0 m/s, and it is subject to gravitational acceleration (g = 9.8 m/s²) acting downwards.
- **Ball B** is projected upwards with an initial velocity (u_B) of 100 m/s. It also experiences gravitational acceleration (g = 9.8 m/s²) acting downwards.

### Step 2: Write the equations of motion
For Ball A (falling down):
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