A particle is moving in a straight line along X-axis and its x-coordinate varies with time as:
`x=t^(2)-4t+6`
Find the distance and displacement of particle in time interval t=0to t=3s.

Explanation

To solve the problem, we need to find both the distance and displacement of the particle moving along the X-axis, given the equation of motion \( x = t^2 - 4t + 6 \) over the time interval from \( t = 0 \) to \( t = 3 \) seconds.

### Step 1: Calculate the position at \( t = 0 \) and \( t = 3 \)

First, we need to find the position of the particle at the given times.

1. **At \( t = 0 \)**:
\[
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