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Height of a tower is 125m and a particle...

Height of a tower is 125m and a particle is dropped from rest from the top of the tower. After two seconds of its fall, another particle is projected downwards with a speed u such that both the particles reach the ground simultaneously. What is the value of u?

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To solve the problem step by step, we will analyze the motion of both particles and use the equations of motion under gravity. ### Step 1: Understand the motion of the first particle (A) - The first particle is dropped from the top of a tower of height \( h = 125 \, \text{m} \). - It is dropped from rest, so its initial velocity \( u_A = 0 \). - The time taken for particle A to reach the ground is \( t_A \). ### Step 2: Calculate the time taken by particle A to reach the ground ...
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