A woman starts from her home at `9.00` a. m., walks with a speed of `5 km h^(-1)` on straight road up to her office `2.5 km`away, stays at the office up to `5.00 p. m.`, and returns home by an auto with a speed of `25 kmh^(-1)`. Plot the position-time graph of the woman taking home as origin.

Explanation

Time taken by woman to reach office `=("distance")/("speed")`
As distance =2.5km, speed =5km/h
Therefore, time t=2.5/5=0.5hr
`therefore` Woman reach office at 9.30 A.M.
Time taken by woman to return home `=(2.5)/(25)=0.1` hr
=6min
`rArr` Woman reaches back to home at 5.06P.M.